12-17

Today in Physics class with Mr. Manning, we discussed vector problems with trig functions. When we arrived in class, we picked up page 24 and were ready to begin. Mr. Manning decided that first we would check over the homework from yesterday. We pulled out our papers and carefully checked over each question. Next, Mr. Manning put a daily question on the board. The daily question was a right triangle with one side labeled 3.9m and another side labeled 32.6m. We had to find the third side and the missing angles. The first step in solving this problem is to find the third side by using the Pythagorean theorem. When we plugged the numbers into the Pythagorean theorem the answer of the third side was 32.8m. Next we had to find the measurements of the angles. We used the trig function tangent and set up the problem like this. We found that the measurement of the angle was 6.8˚. We knew that the right angle is equal to 90˚ so we added 6.8 to 90 and got 96.8˚. We knew that triangles add up to 180˚, so when we subtracted 96.8 from 180 we got 83.2˚, which was the measurement of the last angle. After finishing the daily question, Mr. Manning decided to do another sample problem, just like the problem from the daily question. After we completed the sample problem, he set us off on our own to work on page 24. Page 24 consisted of more vector problems with trig functions. Mr. Manning told the class to finish the worksheet for homework. The work to find the 6.8 degree angle from the daily question is in the image.